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=2Y^2-9Y+10
We move all terms to the left:
-(2Y^2-9Y+10)=0
We get rid of parentheses
-2Y^2+9Y-10=0
a = -2; b = 9; c = -10;
Δ = b2-4ac
Δ = 92-4·(-2)·(-10)
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-1}{2*-2}=\frac{-10}{-4} =2+1/2 $$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+1}{2*-2}=\frac{-8}{-4} =+2 $
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